Ohoh, now we need to flatten the 3 rd AND the 5 th, since neither the X or the X are on the A major scale. This gives us the notes F#, A and C#, which is the F# minor triad, therefore the sixth chord in the key of A is F# minor. We have to lower the 3 rd to the flattened 3 rd. We get the notes E, G# and B, which is the E major triad, therefore the fifth chord in the key of A is E major.Īgain, we need to modify our 3 rd note, which would be a X, since that note is not in the key of A. We get the notes D, F# and A, which is the D major triad, therefore the fourth chord in the key of A is D major.Īgain, the 1 st, 3 rd and 5 th of the E major scale are in the key of A, so we don’t need to modify any of the notes. This time we’re in luck, the 1 st, 3 rd and 5 th of the D major scale are in the key of A, so we don’t need to modify any of the notes. This gives us the notes C#, E and G#, which is the C# minor triad, therefore the third chord in the key of A is C# minor. So our 3 rd note would be a E#, but we can’t have that, since that note is not in the key of A. All of these notes are on the A major scale as well, therefore the second chord in the key of A is B minor. This gives us the notes B, D and F#, which is the B minor triad. ![]() So our 3 rd note for would be a D#, but we can’t have that, since that note is not in the key of A major (not on the A major scale). This gives us the notes A, C# and E, which is the A major triad, therefore the first chord in the key of A is A major. Now let’s calculate the quality of each chord in the key of A.
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